![]() ![]() You can also extract all the non-zero diagonal entries from a given matrix using the spdaigs() function. The values are changed, and the new matrix is saved in the variable matrix2. ![]() In the above code, we changed the values of the main diagonal of matrix1. For example, let’s change the main diagonal entries of the above tridiagonal matrix. To do that, pass the new values in the first argument, the place of the values as the second argument, and the matrix whose values you want to change as the third argument. You can also change the diagonal values of a given matrix using the springs() function. You can create the diagonal matrix with as many values as you want. ![]() In the above code, we made a 5x5 tridiagonal matrix with the diagonal entries stored inside the three variables: v1, v2, and v3. For example, let’s make a tridiagonal matrix from a given vector. The first argument passed inside the spdiags() function are the values, the second argument is the diagonal places, and the third and fourth argument is the size of the diagonal matrix. To make a diagonal matrix with more than one diagonal or to get all the diagonal entries of a matrix, you can use the spdiags() function in MATLAB. Make Diagonal Matrix Using spdiags() Function in MATLAB Check this link for more information about the diag() function. ![]() You can also get the diagonal entries above and below the main diagonal using the second argument inside the diag() function as we used above to make the diagonal matrix with elements above the main diagonal. In the above code, we used the diag() function to find the diagonal entries from the given matrix, and you can see the function returned the diagonal entries of the given matrix. For example, let’s get the main diagonal entries from a given matrix. You can also use the diag() function to get the diagonal entries from a matrix. As you can see, the size of the diagonal is 6圆 now because the vector is placed above the main diagonal, and to ensure all the elements are placed inside the matrix, the size of the matrix increased. In the above code, we created a diagonal matrix with the elements placed above the main diagonal. For example, let’s place the vector above the main diagonal. If the second argument is less than 0, the vector will be placed below the main diagonal. If the second argument is greater than 0, the vector will be placed above the main diagonal. If the second argument is equal to 0, the vector will be placed on the main diagonal. You can also change the position of the diagonal by using a second argument inside the diag() function. If the number of elements is 5, then the diagonal matrix will be 5x5. The diag() function creates a square matrix depending on the number of elements present inside the given vector. In the above code, we made a 5x5 diagonal matrix with the diagonal entries stored in the variable vector. For example, let’s make a diagonal matrix from a given vector. To make a diagonal matrix or to get the diagonal entries of a matrix, you can use the diag() function in MATLAB. Make Diagonal Matrix Using diag() Function in MATLAB Please verify that my interpretation of your loop-based solution is what you are really after.In this tutorial, we will discuss how to make a diagonal matrix using the diag() and spdiags() function in MATLAB. Note, I've pasted some sample code for testing purposes below. I then assign the transpose of A (because you want rows not columns) to the linear index in the solution array. Soln2 = zeros(M, M, (1:M+1:M*M)', (0:M^2:(N-1)*M^2))) = A' Įssentially all I've done is pre-allocate the solution 3d array, and then used bsxfun to construct a linear index of all the diagonals, moving along the 3rd dimension. If this is correct, then one answer is as follows: %# A loop-less solution However, it seems reasonably likely that what you actually are trying to ask is: How do I build a 3d array where each diagonal (moving along the 3rd dimension) is a row from A, without doing a loop? I'm fairly sure your example code contains a couple of typos, since currently the matrix A serves no purpose, nor does your looping subscript j. UPDATE: I've edited the question to fix the typos in the sample code. ![]()
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